4k^2+9k+2=0

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Solution for 4k^2+9k+2=0 equation: 



4k^2+9k+2=0

a = 4; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·4·2
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-7}{2*4}=\frac{-16}{8}
=-2
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+7}{2*4}=\frac{-2}{8}
=-1/4
$

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